Energy Losses in Pharmaceutical Engineering: The change in velocity of the fluid in a flow (either in magnitude or direction) induces large-scale turbulence due to the formation of eddies. So, a portion of energy possessed by the flowing fluid is ultimately dissipated as heat by radiation and is considered to be the loss of energy. Some of the reasons for loss of energy caused by the change in velocity are sudden pipe enlargement, sudden contraction, entrance to a pipe from a large vessel, exit from a pipe, obstruction in the flow passage, gradual contraction or enlargement, bends, and various pipe fittings, etc. These losses of energy are termed as 'minor' losses because the magnitude of these losses is quite small compared to the loss due to friction in long pipes which are distinguished as 'major losses'. The 'minor losses' are confined to a very short length of the passage of the flowing liquid. The analytical expressions representing the loss of energy for the above cases are discussed below.
Energy Loss by Sudden Enlargement
Fig.1: Flow-Through Sudden Enlargement in a Pipe |
Consequently, the flow
separates from the boundary, forming turbulent eddies that result in the loss
of energy dissipated as heat by radiation. If P1, V1, and
P2, V2 are the pressures and velocities of the flow of
liquid in the narrower and wider pipe, respectively, then by continuity
equation, the discharge (Q) is,
Q = A1V1
= A2V2 .....(1)
The force acting on the
liquid in the controlled volume in the direction of flow is expressed as
P1A1
+ P1 (A2 – A1) – P2A2 =
(P1 – P2) A2 ...(2)
Using Newton's second law
for the rate of change of momentum and the head loss between two sections ‘1'
and ‘2' due to sudden enlargement, upon applying Bernoulli's equation we get
`h_1=\frac{(V_1-V_2)^2}{2g}.....(3)`
Using continuity
equation, equation (3) may be expressed as,
`h_1=\frac{V_1^2}{2g}\left(1-\frac{A_1}{A_2}\right)^2=\frac{V_2^2}{2g}\left(\frac{A_2}{A_1}-1\right)^2....(4)`
The equations (3) and
(4) is the expression for head loss due to sudden enlargement.
Energy Loss by Sudden Contraction
Fig.2: Flow-Through Sudden Contraction in a Pipe |
As the liquid flows from
the wider pipe to the narrower pipe, a vena-contract is formed and is followed
by further widening of the liquid stream to fill up completely the narrower
pipe. In between the vena contract and the wall of the pipe, a lot of eddies have
formed that account for considerable dissipation of energy. In this region, the
flow pattern is almost similar to that of sudden enlargement.
In general, the loss of
head due to sudden contraction is expressed as:
`Loss\ of\ head\ (h_L)=0.5\times\frac{V_2^2}{2g}.....(5)`
Energy Loss at Pipe Entrance
Energy loss at the
entrance to the pipe is also called 'inlet loss'. It occurs when the liquid
enters the pipe from a large vessel (or tank). The flow pattern is similar to
that of sudden contraction. In general, for a sharp-cornered entrance, the loss
of head at the entrance is expressed as:
`Loss\ h_L=0.5\times\frac{V_2^2}{2g}.....(6)`
where V2 is
the mean velocity of flow of liquid in the pipe.
Energy Loss at Pipe Exit
The outlet end of a pipe
carrying liquid may be either left free or connected to a large reservoir. The
liquid leaving the pipe possesses some kinetic energy corresponding to the
velocity of the flow in the pipe which is ultimately dissipated either in the
form of free jet or turbulence in the reservoir depending on the outlet
condition in the pipe. The loss may be determined by using Eq. (6) with the
conditions for which A2 → ∞. So, the loss of head at the exit of the
pipe expressed as
`Loss\ h_{L\ }=\ frac{V^2}{2g}....(7)`
where V is the mean
velocity of flow of liquid in the pipe.
Energy Loss by Obstruction in Flow Passage
The loss of energy due to
flow obstruction in a pipe occurs due to the sudden reduction in the
cross-sectional area followed by an abrupt enlargement of the stream beyond the
obstruction, Fig.3.
Fig.3: Flow Through a Pipe With Obstruction |
Consider a pipe flow (cross-sectional area of the pipe is A) in which obstruction is placed with maximum cross-sectional area ‘a’. As the flow passage is reduced to (A − a), a vena-contract is formed beyond which the flow becomes uniform after a certain distance from vena-contracta. If Vc and V be the velocities at vena-contracta and at the section where the flow is uniform, then the loss of head due to obstruction can be deduced as
`h_L=\frac{V^2}{2g}\left[\frac A{C_c\ (A\ -\ a)}-1\right]....(8)`
Make sure you also check our other amazing Article on : Bernoulli’s Theorem and Its Applications